-b^2-3b+18=0

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Solution for -b^2-3b+18=0 equation:


Simplifying
-1b2 + -3b + 18 = 0

Reorder the terms:
18 + -3b + -1b2 = 0

Solving
18 + -3b + -1b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3 + -1b)(6 + b) = 0

Subproblem 1

Set the factor '(3 + -1b)' equal to zero and attempt to solve: Simplifying 3 + -1b = 0 Solving 3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1b = 0 + -3 -1b = 0 + -3 Combine like terms: 0 + -3 = -3 -1b = -3 Divide each side by '-1'. b = 3 Simplifying b = 3

Subproblem 2

Set the factor '(6 + b)' equal to zero and attempt to solve: Simplifying 6 + b = 0 Solving 6 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + b = 0 + -6 Combine like terms: 6 + -6 = 0 0 + b = 0 + -6 b = 0 + -6 Combine like terms: 0 + -6 = -6 b = -6 Simplifying b = -6

Solution

b = {3, -6}

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